rfcurry Posted June 25, 2014 Share Posted June 25, 2014 I read somewhere recently that the Bayer filter over the sensor typically absorbs 2/3rds of the incident light. This makes sense if the photons are in the wavelengths antithetical to the dye. So, if the light is green and the cel green, the R and B don't make it through to the sensor. That is, however, a loss that the human eye, for example, doesn't experience. Here is the normalized absorption spectra of a trout's retina (sorry, didn't have time to dig out a human's): http://overmywaders.com/images/4graphs.jpg As you can see, a photon at 390 nm striking a trout's Red cone will be absorbed by the opsin slightly less than the Green and the Blue - which appear equal at that point. However, no matter the cone type, the 390 nm will be absorbed by, and activate, the opsin of that cone. [Even better with the rods.] What does the absorption spectra for the Bayer filter look like? Do we get the same benefit from RGB at 390 nm as in the graph above? Sorry if this is a stupid question. I'm not fully caffinated yet but curious nevertheless. :) Link to comment
rfcurry Posted June 25, 2014 Author Share Posted June 25, 2014 I found a partial answer here -- http://www.dpreview.com/forums/thread/2878305 Link to comment
DaveO Posted June 26, 2014 Share Posted June 26, 2014 Reed, This post gives links to modern sensorshttp://www.ultraviol...ormance-curves/ I have tried, without success, but perhaps not very hard, to get UV absorption curves on the dyes used in the Bayer array Dave Link to comment
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